Tennis W15 Phan Thiet Vietnam: A Glimpse into Tomorrow's Matches
The Tennis W15 Phan Thiet Vietnam tournament is set to captivate tennis enthusiasts with its exciting lineup of matches scheduled for tomorrow. As the sun rises over the picturesque coastal city of Phan Thiet, players will be gearing up for a day filled with intense competition and thrilling gameplay. This event, part of the ATP Challenger Tour, promises to showcase some of the world's most talented rising stars in tennis. With a rich history and a vibrant atmosphere, the tournament is not just about the matches but also about celebrating the sport and its growing fanbase in Vietnam.
Understanding the Tournament Structure
The Tennis W15 Phan Thiet Vietnam follows a standard tournament format, featuring singles and doubles competitions. The singles draw typically includes 32 players, while the doubles draw comprises 16 pairs. These players compete in a knockout format, progressing through rounds until the finals are reached. The tournament is known for its fast-paced matches on hard courts, which test both skill and endurance.
Key Players to Watch
Tomorrow's matches feature several notable players who have been making waves in recent tournaments:
- Player A: Known for his powerful serve and aggressive baseline play, Player A has been climbing the rankings rapidly.
- Player B: With exceptional agility and strategic prowess, Player B is a formidable opponent on any court.
- Player C: A wildcard entry with impressive performances in qualifiers, Player C brings an element of surprise to the tournament.
Betting Predictions: Expert Insights
Betting enthusiasts have their eyes set on tomorrow's matches, with expert predictions offering insights into potential outcomes:
- Match Prediction 1: Player A vs. Player D - Experts favor Player A due to his recent form and strong head-to-head record against Player D.
- Match Prediction 2: Player B vs. Player E - This match is anticipated to be closely contested, but Player B's tactical acumen gives him a slight edge.
- Doubles Prediction: Pair X vs. Pair Y - Pair X's chemistry and experience make them favorites to win this doubles encounter.
Tournament Atmosphere and Fan Engagement
The Tennis W15 Phan Thiet Vietnam is more than just a sporting event; it's a celebration of tennis culture in Vietnam. Fans from all over gather to support their favorite players, creating an electrifying atmosphere at the stadium. Local vendors offer traditional Vietnamese snacks and drinks, adding to the festive vibe. Additionally, interactive fan zones provide opportunities for fans to engage with players through autograph sessions and photo ops.
Historical Significance
This tournament holds historical significance as it marks one of the few ATP Challenger events held in Southeast Asia. It serves as a platform for local talent to compete on an international stage and gain exposure. Over the years, it has become a staple event that attracts both local fans and international visitors eager to experience Vietnamese hospitality alongside world-class tennis.
Detailed Match Analysis
Tomorrow's schedule includes several high-stakes matches that promise excitement from start to finish:
Morning Session Highlights
- Morning Match 1: An early showdown between two top-seeded players sets the tone for what promises to be an exhilarating day of tennis.
- Morning Match 2: This match features an underdog story where an emerging talent aims to upset higher-ranked opponents.
Afternoon Session Highlights
- Afternoon Match 1: A classic battle between two seasoned veterans who have shared numerous memorable encounters on court.
- Semifinal Preview: As we approach evening play, semifinalists are poised for action that could determine their path forward in this prestigious tournament.s>tv>w>x>y>{|}~
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Eve<|repo_name|>sharadchauhan/CS-101<|file_sep|>/Lecture Notes/week7/lecture7.md
# Lecture 7: Recursion
## Learning Objectives
* Define recursion.
* Explain how recursive methods work.
* Recognize when recursion can be used.
## What Is Recursion?
Recursion occurs when a method calls itself.
java
public void recursiveMethod() {
recursiveMethod();
}
Recursive methods are useful when solving problems that have repeating sub-problems.
For example:
* Compute Fibonacci numbers.
* Compute factorial values.
* Perform binary search.
## How Does Recursion Work?
To understand how recursion works we need to understand call stacks.
A call stack keeps track of active method invocations.
When we invoke `recursiveMethod`, it gets added onto top of call stack:
+-------------------+
| recursiveMethod() |
+-------------------+
When `recursiveMethod` invokes itself again (and again), each invocation gets added onto top of call stack:
+---------------------+
| recursiveMethod() |
+---------------------+
| recursiveMethod() |
+---------------------+
| recursiveMethod() |
+---------------------+
Each invocation waits for other invocations above it (on top of call stack) before returning.
So after three invocations (three items on call stack), `recursiveMethod` returns once after third invocation returns:
+---------------------+
| recursiveMethod() | <- returns here
+---------------------+
| recursiveMethod() |
+---------------------+
| recursiveMethod() |
+---------------------+
Then second invocation returns:
+---------------------+
| recursiveMethod() | <- returns here
+---------------------+
| recursiveMethod() | <- returns here
+---------------------+
Finally first invocation returns:
+---------------------+
| recursiveMethod() | <- returns here
+---------------------+
The last item on call stack always returns first!
This process continues until there are no more items left on call stack:

### Stack Overflow
When there are too many items on call stack then there isn't enough memory available anymore!
This results in `StackOverflowError`.
### Base Case
In order avoid `StackOverflowError`, we need base case(s).
Base case(s) should not result in further method invocations!
For example:
java
public void printHello(int n) {
if (n <= 0) return;
System.out.println("Hello");
printHello(n - 1);
}
In this example base case occurs when `n <= 0`.
Base case causes method invocation chain stops by returning without invoking itself again.
## Example: Factorial Method
Factorial method computes factorial value using recursion.
java
public int factorial(int n) {
if (n == 0) return 1;
return n * factorial(n - 1);
}
Here base case occurs when `n == 0`.
To compute factorial value we multiply current number (`n`) by factorial value of next smaller number (`n - 1`).
### How Does Factorial Method Work?
Let us trace execution flow step-by-step using following input: `factorial(5)`.
Initially call stack looks like this:

Since `5 != 0`, first line inside body executes resulting into multiplication operation (`5 * factorial(4)`).
Next line executes resulting into further multiplication operation (`5 * (4 * factorial(3))`).
And so on...
Eventually base case occurs when input becomes zero resulting into following sequence of operations:

Now let us evaluate these operations from rightmost side since they depend upon each other!
First we evaluate rightmost operation resulting into following state:

Next we evaluate next operation resulting into following state:

And so on...
Until eventually final result becomes available resulting into following state:

### Factorial Method In Practice
Let us see how we can use factorial method in practice!
We can use this method inside another method called `printStars`.
java
public static void printStars(int n) {
for (int i = 0; i < n; i++) System.out.print("*");
System.out.println();
}
public static int factorial(int n) {
if (n == 0) return 1;
return n * factorial(n - 1);
}
public static void main(String[] args) {
for (int i = factorail(5); i >= factorail(0); i--) {
printStars(i);
}
}
This program prints out pattern similar as follows:
#### Explanation
First line inside loop calls `printStars(i)` where value of `i` initially equals five!
So first line prints out five stars followed by newline character resulting into following output:
Next iteration happens when value of `i` decrements down by one!
So next iteration prints out four stars followed by newline character resulting into following output:
And so on...
Until eventually loop terminates once value of `i` reaches zero!
#### Output
## Example: Fibonacci Method
Fibonacci method computes Fibonacci number using recursion.
java
public int fibonacci(int n) {
if (n == 0 || n == 1) return n;
return fibonacci(n - 2) + fibonacci(n -1);
}
Here base cases occur when either input equals zero or one.
To compute Fibonacci number we add together two previous Fibonacci numbers starting from index zero!
### How Does Fibonacci Method Work?
Let us trace execution flow step-by-step using following input: `fibonacci(6)`.
Initially call stack looks like this:
Since neither condition evaluates true (`6 != O && O != l`) then next line executes resulting into addition operation (`fibonacci(4) + fibonacci(5)`).
Next two lines execute recursively causing two more addition operations.
And so on...
Eventually base cases occur causing some operations stop executing further!
Now let us evaluate these operations from rightmost side since they depend upon each other!
First we evaluate rightmost operation causing another addition operation.
Next we evaluate next operation causing yet another addition operation.
And so on...
Until eventually final result becomes available.
### Fibonacci Method In Practice
Let us see how we can use fibonacci method in practice!
We can use this method inside another method called printFibonacciPattern.
This program prints out pattern similar as follows:
#### Explanation
First line inside loop calls printStars(fibonacci(i)) where value of i initially equals zero!
So first iteration prints out zero stars followed by newline character resulting into following output:
Next iteration happens when value of i increments up by one!
So second iteration prints out one star followed by newline character resulting into following output:
And so on...
Until eventually loop terminates once value reaches six!
#### Output
## When Should We Use Recursion?
We should only use recursion if problem naturally fits recursion model or if problem cannot easily solved without recursion! Otherwise iterative solution will be better choice since iterative solutions tend consume less memory than corresponding recursive solutions.<|file_sep[TOC]
# Lecture Notes Week #9
## Learning Objectives
* Understand why Java uses references instead pointers
* Understand difference between primitive types vs reference types
* Understand difference between primitive types vs objects
* Understand concept behind immutable objects
* Know difference between mutable & immutable objects
* Know difference between shallow copy & deep copy
* Know difference between pass-by-value & pass-by-reference
## References vs Pointers
Java uses references instead pointers because references don't allow pointer arithmetic which makes Java programs safer than programs written using languages that support pointers such as C++ or C!
A reference points towards an object whereas pointer points towards address!
There isn't any difference between references & pointers except they behave differently!
For example consider below code snippet written using C++ language which supports pointers!
cpp
#include
class MyInteger {
private:
int data;
public:
MyInteger(int d): data(d){}
void setData(int d){
data = d;
}
int getData(){
return data;
}
};
void increment(MyInteger& m){
m.setData(m.getData()+10);
}
void main(){
MyInteger m(100);
cout << "Before incrementing : " << m.getData()<< endl;
increment(m);
cout << "After incrementing : " << m.getData()<< endl;
}
Above code outputs below output:
Before incrementing : **100**
After incrementing : **110**
Above code shows that passing argument by reference allows caller function access actual object instead copy created during function invocation! So changes made within callee function affect original object passed as argument!
Now consider below code snippet written using Java language which doesn't support pointers!
java
class MyInteger {
private int data;
public MyInteger(int d){
data = d;
}
void setData(int d){
data = d;
}
int getData(){
return data;
}
}
void increment(MyInteger m){
m.setData(m.getData()+10);
}
void main(){
MyInteger m = new MyInteger(100);
System.out.println("Before incrementing : "+m.getData());
increment(m);
System.out.println("After incrementing : "+m.getData());
}
Above code outputs below output:
Before incrementing : **100**
After incrementing : **110**
Although Java doesn't support passing arguments by reference still above code produces same effect as passing arguments by reference because Java passes references during function invocation instead actual objects! So changes made within callee function affect original object passed as argument even though argument is passed by value!
In above code snippet variable 'm' stores reference towards MyInteger object whereas 'increment' parameter stores copy created during function invocation referencing same MyInteger object referenced through 'm'. So changes made within callee function affect original object passed as argument even though argument is passed by value because both 'm' & 'increment' parameter store reference towards same MyInteger object!
Note that if callee function creates new object then caller won't see those changes because caller stores reference towards different object than callee creates during function execution! For example consider below modified version of above code snippet where callee creates new instance rather than changing existing instance passed as argument!
java
class MyInteger {
private int data;
public MyInteger(int d){
data = d;
}
void setData(int d){
data = d;
}
int getData(){
return data;
}
}
void increment(MyInteger m){
m = new MyInteger(m.getData()+10);
}
void main(){
MyInteger m = new MyInteger(100);
System.out.println("Before incrementing : "+m.getData());
increment(m);
System.out.println("After incrementing : "+m.getData());
}
Above code outputs below output:
Before incrementing : **100**
After incrementing : **100**
Above code shows that if callee creates new instance rather than changing existing instance passed as argument then caller won't see those changes because caller stores reference towards different object than callee creates during function execution!
## Primitive Types vs Reference Types
Primitive types store values directly whereas reference types store references towards objects storing values indirectly via heap memory allocation !
Primitive types include boolean , byte , short , char , int , long , float & double whereas everything else including arrays & custom classes are considered reference types !
Following table summarizes differences between primitive types & reference types !
| Property | Primitive Type | Reference Type |
| Size | Size depends upon architecture ! | Size depends upon JVM implementation ! |
| Memory Allocation | Allocated directly onto stack memory ! | Allocated indirectly onto heap memory via stack memory allocation ! |
| Default Value | Predefined default values exist ! For example boolean variables default initialized with false while integer variables default initialized with zero ! | Null values exists unless explicitly initialized otherwise nulls exist otherwise ! For example arrays default initialized with null unless explicitly initialized otherwise nulls exist otherwise ! Custom classes also default initialized with null unless explicitly initialized otherwise nulls exist otherwise ! Note that class instances cannot be created automatically without explicit constructor calls unlike primitive type instances which can be created automatically without explicit constructor calls since predefined constructors exist implicitly ! To create class instances explicit constructor calls required like shown below example showing creation MyClass instance named myObject via calling MyClass constructor explicitly !
MyClass myObject=new MyClass();
Note that MyClass constructor must exist either explicitly defined or implicitly defined via compiler generated no arguments constructor provided no constructors explicitly defined !
If multiple constructors exist then compiler won't generate implicit no arguments constructor !
Example showing compilation error due absence implicit no arguments constructor caused due presence explicit constructors !
class MyClass {
MyClass(){ }
MyClass(String s){ }
MyClass(String s,int i){ }
}
Note that above class compiles successfully since at least one implicit no arguments constructor exists !
But note that below class doesn't compile successfully since absence implicit no arguments caused due presence multiple explicit constructors !
class MyClass {
MyClass(String s){ }
MyClass(String s,int i){ }
}
Error message shown below indicates absence implicit no arguments constructor caused due presence multiple explicit constructors !
The type MyClass must implement abstract type java.lang.Comparable or must declare abstract or concrete comparator . Class file contains class definition for MyClass but does not contain definition for any public java.lang.Comparable.compareTo(com.company.MyClass)argx methods .
Multiple markers at this line :
-The type MyClass must implement abstract type java.lang.Comparable or must declare abstract or concrete comparator .
-Class file contains class definition for MyClass but does not contain definition for any public java.lang.Comparable.compareTo(com.company.MyClass)argx methods .
At com/company/MyClass.java:[8] error :
-The type MyClass must implement abstract type java.lang.Comparable or must declare abstract or concrete comparator .
At com/company/MyClass.java:[8] error :
-Class file contains class definition for MyClass but does not contain definition for any public java.lang.Comparable.compareTo(com.company.MyClass)argx methods .
Compilation failed .
| Access Speed | Accessed faster than reference types since stored directly onto stack memory accessed faster compared heap memory accessed slower compared stack memory accessed faster !
|
| Default Constructor Availability | Predefined implicit no arguments constructors exists !
|
| Type Name Format | Type names end either suffixes like boolean , byte , short , char , int , long , float & double indicating primitive nature !
| Type names end either suffixes like String indicating non-primitive nature !
| Type names end either suffixes like String indicating non-primitive nature !
| Type names end either suffixes like String indicating non-primitive nature !
| Type names end either suffixes like String indicating non-primitive nature !
| Type names end either suffixes like String indicating non-primitive nature !
| Property Name
| Primitive Type
| Reference Type
| Explanation
|
| Size
| bite
| 'b'
| -
| '*'b'
| -
| '*' indicates size varies depending upon JVM implementation
|
| 'byte'
| '-'
| 'String'
| '-'
| '*' indicates size varies depending upon JVM implementation
|
| 'short'
| '-'
| 'String[]'
|
| 'char'
|
| 'int'
|
| 'long'
|
| 'float'
|
| 'double'
|
| |